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USACO0612

Lazy Cow

Diamond V 다이아몬드 V
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설명

Bessie is hard at work preparing test cases for the USA Cowmputing Olympiad
February contest. Each minute, she can choose to not prepare any tests,
expending no energy; or expend \(3^{a-1}\) energy preparing \(a\) test cases, for
some positive integer \(a\).

Farmer John has \(D\) (\(1\le D\le 2\cdot 10^5\)) demands. For the \(i\)th demand, he
tells Bessie that within the first \(m_i\) minutes, she needs to have prepared at
least \(b_i\) test cases in total (\(1\le m_i\le 10^6, 1 \leq b_i \leq 10^{12}\)).

Let \(e_i\) be the smallest amount of energy Bessie needs to spend to satisfy the
first \(i\) demands. Print \(e_1,\dots,e_D\) modulo \(10^9+7\).

Problem credits: Brandon Wang and Claire Zhang

제약

SCORING

  • Inputs 4-5: \(D\le 100\) and \(m_i \le 100\) for all \(i\)
  • Inputs 6-8: \(D\le 3000\)
  • Inputs 9-20: No additional constraints.

Problem credits: Brandon Wang and Claire Zhang

입력 형식

The first line contains \(D\). The \(i\)th of the next \(D\) lines contains two
space-separated integers \(m_i\) and \(b_i\).

출력 형식

Output \(D\) lines, the \(i\)th containing \(e_i \text{ mod } 10^9+7\).

예제 1
입력
4
5 11
6 10
10 15
10 30
출력
21
21
25
90
설명

For the first test case,

  • \(i=1\): If Bessie creates \([2, 3, 2, 2, 2]\) test cases on the first \(5\) days, respectively, she would have expended \(3^1 + 3^2 + 3^1 + 3^1 + 3^1 = 21\) units of energy and created \(11\) test cases by the end of day \(5\).
  • \(i=2\): Bessie can follow the above strategy to ensure \(11\) test cases are created by the end of day \(5\), and this will automatically satisfy the second demand.
  • \(i=3\): If Bessie creates \([2, 3, 2, 2, 2, 0, 1, 1, 1, 1]\) test cases on the first \(10\) days, respectively, she would have expended \(25\) units of energy and satisfied all demands. It can be shown that she cannot expend less energy.
  • \(i=4\): If Bessie creates 3 test cases on each of the first \(10\) days she would have expended \(3^{2}\cdot 10 = 90\) units of energy and satisfied all demands.

For each \(i\), it can be shown that Bessie cannot satisfy the first \(i\) demands using
less energy.

예제 2
입력
2
100 5
100 1000000000000
출력
5
627323485
예제 3
입력
20
303590 482848034083
180190 112716918480
312298 258438719980
671877 605558355401
662137 440411075067
257593 261569032231
766172 268433874550
8114 905639446594
209577 11155741818
227183 874665904430
896141 55422874585
728247 456681845046
193800 632739601224
443005 623200306681
330325 955479269245
377303 177279745225
880246 22559233849
58084 155169139314
813702 758370488574
929760 785245728062
출력
108753959
108753959
108753959
148189797
148189797
148189797
148189797
32884410
32884410
32884410
32884410
32884410
32884410
32884410
3883759
3883759
3883759
3883759
3883759
3883759
문제 정보

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출처 올림피아드 > USACO > 2023-2024 > February > Platinum

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Lazy Cow

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출제자 난이도 Diamond V 다이아몬드 V 의견 0 / 50 공개 집계 (커뮤니티 난이도, 주요 주제, 품질)는 의견이 충분히 모이면 공개됩니다.

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