The local pie shop is offering a promotion - all-you-can-eat pies!
Obviously, you can’t pass up this offer.
The shop lines up \(N\) pies from
left to right - the \(i\)th pie
contains \(A_i\) grams of sugar.
Additionally, another \(M\) pies are
provided - the \(i\)th of these
contains \(B_i\) grams of sugar.
You are first allowed to insert each of the \(M\) pies from the second group anywhere
into the first list of \(N\) pies, such
as at its start or end, or in between any two pies already in the list.
The result will be a list of \(N+M\)
pies with the constraint that the initial \(N\) pies are still in their original
relative order.
Following this, you are allowed to take one walk along the new line
of pies from left to right, to pick up your selection of all-you-can-eat
pies! When you arrive at a pie, you may choose to add it to your pile,
or skip it. However, because you’re required to keep moving, if you pick
up a certain pie, you will not be able to also pick up the pie
immediately after it (if any). In other words, you cannot eat
consecutive pies in this combined list.
Being a pie connoisseur, your goal is to maximize the total amount of
sugar in the pies you pick up from the line. How many grams can you
get?
The first line of input contains the integer \(N~(1 \leq N \leq 3000)\). The next \(N\)
lines contain one integer \(A_i~(1 \leq A_i \leq 10^5)\), describing the
integer number of grams of sugar in pie \(i\) in the group of \(N\) pies.
The next line contains \(M~(0 \leq M \leq 100)\), the number of pies in
the second list. The next \(M\) lines
contain one integer \(B_i~(1 \leq B_i \leq 10^5)\), describing the
integer number of grams of sugar in pie \(i\) in the group of \(M\) pies.
For 20% of the marks for this question, \(M=0\). For another 20% of the marks for
this question \(M=1\). For another 20%
of the marks for this question \(M\leq 10\).
Output the maximum number of grams of sugar in all the pies that you
are able to pick up.
5
10
12
6
14
7
3
1
8
244Place the pies in the order
10, 1, 12, 2, 8, 6, 14, 7
(that is, insert the pie with 1 gram of sugar between 10 and 12, and
insert pies with 2 and 8 grams of sugar, in that order, between pies 12
and 6). Then, we can grab \(10+12+8+14=44\) grams of sugar, which is
maximal.