J1. Quadrant Selection
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Time limit: 1 second
A common problem in mathematics is to determine which quadrant a
given point lies in. There are four quadrants, numbered from 1 to 4, as
shown in the diagram below:
For example, the point A, which is at coordinates (12, 5) lies in
quadrant 1 since both its \(x\) and
\(y\) values are positive, and point
\(B\) lies in quadrant 2 since its
\(x\) value is negative and its \(y\) value is positive.
Your job is to take a point and determine the quadrant it is in. You
can assume that neither of the two coordinates will be \(0\).
\((-1000 \leq x \leq 1000; x \not= 0)\)
\((-1000 \leq y \leq 1000; y \not= 0)\)
The first line of input contains the integer \(x\) \((-1000 \leq x \leq 1000; x \not= 0)\). The second line of input contains the integer \(y\) \((-1000 \leq y \leq 1000; y \not= 0)\).
Output the quadrant number (\(1\),
\(2\), \(3\) or \(4\)) for the point \((x,y)\).
12
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J1. Quadrant Selection
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J1. Quadrant Selection